[strongSwan] Microsoft Azure Virtual Network?
John Connett
jrc at skylon.demon.co.uk
Fri Aug 3 12:17:09 CEST 2012
On Fri, 03 Aug 2012 10:14:01 +0100, Martin Willi <martin at strongswan.org>
wrote:
>> > 10[CFG] <2> looking for pre-shared key peer configs matching
>> > 192.168.199.10...168.63.60.212[10.4.1.4]
>> > 10[IKE] <2> no peer config found
>>
>> Is this an artifact of the charon / pluto merge in strongSwan 5? Or is
>> "keyexchange=ikev2" not sufficient to cause IKEv2 to be used?
>
> The keyexchange parameter is connection specific, so your connection
> will use IKEv2.
>
> Your peer, however, seems to initiate with IKEv1. You don't have a
> matching connection for IKEv1, hence the negotiation fails with "no peer
> config found".
I have tried "keyexchange=ike" which the ipsec.conf manual page says will
"use IKEv2 when initiating, but accept any protocol version when
responding". However, that doesn't seem to make a difference ...
>> IKE Phase I Parameters:
>> Mode: Main mode
>> Encryption: AES128 or 3DES
>> Integrity: SHA1
>> Diffie-Hellman group: Group 2 (1024 bit)
>> Authentication Method: Pre-shared key
>> Security Association Lifetime: 28800 seconds
>
> Phase 1 proposal is what we define with the "ike" keyword:
>
> ike=aes128-sha1-modp1024!
> leftauth=psk
> rightauth=psk
>
>> IKE Phase II Parameters:
>> Mode: ESP tunnel mode
>> Encryption: AES128 or 3DES
>> Integrity: SHA1
>> Perfect Forward Secrecy: OFF
>> Diffie-Hellman group: Group 2 (1024 bit)
>
> This seems bogus to me, either you have a DH group and use PFS, or not.
> The "esp" keyword in your connection is either
>
> esp=aes128-sha1!
>
> or
>
> esp=aes128-sha1-modp1024!
I have removed the 3des entries from ike and esp. Either with or without
"-modp1024" I am still seeing "no peer config found".
Am I missing something fundamental such as needing two separate conn
section depending on which end initiates? Or is there a way to ensure
that the right (remote) end always initiates and the left end listens?
Could I need "xauthpsk" rather than "psk".
Apologies if these have obvious answers but I am very new to this!
Many thanks for the help
--
John Connett
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